Linear Equations

By ellipticcurves

Let us begin with a curve

C: ax+by = c,

with a,b,c\in K. Without loss of generality, we may assume that b\neq 0. Then the map C\to {\mathbb A}^1 given by (x,y)\mapsto x is a morphism defined over K with an inverse morphism {\mathbb A}^1\to C given by x \mapsto (x, (c-ax)/b). Therefore, every line C in {\mathbb A}^2 that is defined over K is isomorphic to {\mathbb A}^1. In particular, one can establish a bijection between C(L) and {\mathbb A}^1(L) = L for all L/K.

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